How to Find One Poisoned Bottle with the Fewest Mice
A binary-encoding solution to a one-round identification puzzle.
Recent posts
Why Two People Must Have the Same Number of Friends
A short graph-theoretic proof using the pigeonhole principle.
The Two-Element Group Hidden in Yes and No
A simple agreement rule on Yes and No forms the cyclic group of order two.
How Many Bits Does a Discrete Vector Need?
A counting argument reveals the minimum storage required for categorical vectors and images.